1.

A dilute solution havingon mole of solute 'S' in 1 kg solvent with molal elevation constant K_(b) Solute undergoes association as follows.2ShArrS_(2)The degree of association of solute alpha is given by the following expression . alpha=(1-i)/(1-1//n) Where, in the number of molecular of solute undergoing association . The degree of associationcan be given as :

Answer»

`alpha =(DeltaT_(B))/(2K_(b))`
`alpha=(2+2DeltaT)/(K_(b))`
`alpha=(K_(b)-DELTAT)/(2DeltaT)`
`alpha=2(K_(b)-DeltaT)/(K_(b))`

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