1.

A diode is connected to 200 V (rms) ac in series with a capacitor as shown in figure. The voltage across the capacitor is

Answer»

220 V
110 V
311.1 V
`200/(sqrt2)V`

Solution :The diode D will conduct for positive half cycle of a.c. SUPPLY because this is forward biased. For NEGATIVE half cycle of a.c. supply , this is reverse biased and does not conduct . So output WOULD be half WAVE rectified and for half wave rectified out put
`V_(rms)=V_0/2=(200sqrt2)/2=200/sqrt2`


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