Saved Bookmarks
| 1. |
A dip circle is set in position after leveling and the dip is found to be alpha . Then it is rotated through 45^(@) away from the magnetic meridian from this position and the dip is found to be beta Show that true dip is given by cot^(2)delta=2(cot^(2)alpha+cot^(2)beta-sqrt(2)cot alphacot beta) |
| Answer» | |