1.

A dip circle lies initally in the magnetic meridian if it is now rotated throughangle thetain the horizontal plane thentangent of the angle ofd dip is chagedin the ratio

Answer»

`1:cos theta`
`cos theta:1`
`1:sin theta`
`sin theta:1`

Solution :Here `TAN delta=(V)/(H)` and `tan delta =(v)/(H cos theta)`
`THEREFORE (tan delta)/(tan delta)=(v)/(H cos theta)xx(H)/(V )=(1)/(cos theta)`


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