InterviewSolution
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InterviewSolution
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A dipole consisting of an electron and a proton separated by a distance of 4 xx 10^(-10)m is situated in an electric field of intensity 3 xx 10^(5) NC^(-1) at an angle of 30^(@) with the field. Calculate dipole and torque acting on it. (e=1.6 xx 10^(-19)C). |
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Answer» Solution :Data SUPPLIED, Charge of an ELECTRON `=|q_(1)|=e=1.6 xx 10^(-19)C` Charge on proton `=|q_(2)| =e =1.6 xx 10^(-19)C` Dipole length `=2a=4 xx 10^(-10)m` Dipole moment `p=2a xx " any of the charge "=4 xx 10^(-10) xx 1.6 xx 10^(-19)=6.4 xx 10^(-29) C.m.` Electric field intensity `E=3 xx 10^(5) NC^(-1), theta=30^(@), sin theta=sin 30^(@)=1/2` Torque,` tau =p E sin theta=6.4 xx 10^(-29) xx 3 xx 10^(5) xx 1/2=9.6 xx 10^(-23)Nm` |
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