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A direct current of `5` amp is superimposed on an alternating current `I=10 sin omega t` flowing through a wire. The effective value of the resulting current will be:A. `7.5A`B. `2sqrt3A`C. `5sqrt3A`D. `15A` |
Answer» Correct Answer - C `I =5 + 10 sin omegat` `bari^(2) = 5^(2) + 10^(2)/(2) =75` `i_(rms) = sqrt(bari^(2)) = 5 sqrt3 A` . |
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