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A direct currenty I flowsin a long straightconductorwhosecross-sectionalhas the fromof a the half-ring of radius R. The samecurrent flows in the oppositedirectionalonga thin condocutorlocatedon the "axis"of the first conductor (point O in FIg). Find teh magneticinteractionforce betweenthem reducedto a unitofthier length. |
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Answer» Solution :The MAGNITUDE FIELD due to the conductorwith semicircular cross section is `B = (mu_(0) I)/(pi^(2) R)` Then `(del F)/(del l) = BI = (mu_(0) l^(2))/(pi^(2) R)` |
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