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A disc and a solid sphere of same mass and radius roll down an inclined plane. The ratio of thhe friction force acting on the disc and sphere isA. `(7)/(6)`B. `(5)/(4)`C. `(3)/(2)`D. depends on angle of inclination |
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Answer» `f=(mgsintheta)/(1+mR^(2)//I)` `d_("disc")=(mgsintheta)/(1+2)=(1)/(3)mgsintheta` `f_("sphere")=(mgsintheta)/(1+5//2)=(2)/(7)mgsintheta` `therefore` the ratio is `(7)/(6)` |
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