InterviewSolution
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InterviewSolution
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A disc of circumference `s` is at rest at a point `A` on a horizontal surface when a constant horizontal force begins to act on its centre. Between `A` and `B` there is sufficient friction toprevent slipping, and the surface is smooth to the right of `B.AB = s`. The disc moves from `A` to `B` in time `T`. To the right of `B`, .A. the angular acceleration of the disc will disappear linear acceleration will remain unchangedB. . linear acceleration of the disc will increaseC. the disc will make one rotation in time `T//2`D. the disc will cover a distance greater than s in further time `T` |
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Answer» Correct Answer - B::C::D Let `P=`external force `F=` force of friction between `A` and `B` `a_(1)=` acceleration between `A` and `B a_(2) =` acceleration beyond `B` `P-F=ma_(1)` `P=ma_(2` `a_(2)gta_(1)` Let `alpha=`angualar acceleration between `A` and `B` For one rotation `theta=2pi=1/2alphaT^(2)` `T=sqrt((4pi)/alpha)= ` time of travel from `A` to `B` angular velocity at `B=omega_(0)=alphaT` For one rotation to the right of `B` `theta=2pi=omega_(B)t` `t=(2pi)/(aT)=(1/2alphaT^(2))/(alphaT)=T/2` |
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