InterviewSolution
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InterviewSolution
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A constant external torque `tau` acts for a very brief period `/_ ` on a rotating system having moment of inertia `I` thenA. the angular velocity of the system will change by `tau/_ //I`B. the angular velocity of the system will change by `tau/_ //I`C. if the system was initially at rest, it will acquire rotational kinetic enegy `(tau/_ )^(2)//2I`D. the kinetic energy of the system will change by `(tau/_ )^(2)//(2I)` |
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Answer» Correct Answer - A::B::C::D Let `L=`angular momentum `tau=(dL)/(dt)` or `dL=taudt` For constant torque `/_L=tau/_ =I/_omega` or `Iomega` (if `omega_(I)=0)` Rotational kinetic energy `=Iomega^(2)//2=(/_L)^(2)//2l` |
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