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The end B of the rod AB which makes angle `theta` with the floor is being pulled with a constant velocity `v_(v)` as shown. The length of the rod is `l`.A. `3/5v_(0)`B. `4/5v_(0)`C. `5/3v_(0)`D. `5/4v_(0)` |
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Answer» Correct Answer - B Let `OA=x, OB=y` `x^(2)+y^(2)=l^(2)` and `x=lcostheta` Different `x^(2)+y^(2)=l^(2)` with respect to time. `2x(dx)/(dt)+2y(dy)/(dt)=0` `V_(B)=(dy)/(dt)=x/y (dx)/(dt)=-V_(A)cottheta=4/5v_(0)darr` |
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