Saved Bookmarks
| 1. |
A disc of mass m and radius r is gently placed on another disc of mass 2m and radius r. The disc of mass 2m is rotating with angular velocity omega_(0) initially.The disc is placed such that axis of both are concident. The coefficient of friction is mu for surfaces of contact Assume that pressure on disc is uniformely distributed. Angular velocity 'omega' when both discs start rotating together without slipping |
|
Answer» `(2omega_(0))/(3)` `V_(A)=omega(lsin30^(@))=V_(0)` `implies omega=(2V_(0))/(l)` `L_(ICR)=(I)_(ICR^(omega))` `(I)_(ICR)=I_(cm)+MD^(2)=(ml^(2))/(12)+m((l)/(2))^(2)=(ml^(2))/(3)` `(I)_(ICR)=((ml^(2))/(3))((2v_(0))/(l))=(2mv_(0)l)/(3)` 
|
|