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A disc of radius `R` is pivoted at its rim. The period for small oscillations about an axis perpendicular to the plane of disc isA. `2pisqrt(R )/(g)`B. `2pi sqrt ((2R)/(g))`C. `2pi sqrt ((2pi)/(3g))`D. `2pi sqrt((3R)/(2g))` |
Answer» Correct Answer - D `I = (1)/(2)mR^(2) + mR^(2) = (3)/(2)mR^(2)` `T = 2pi sqrt((1)/(mgl))` Here `l = R` |
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