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A disc of radiusis rotatating with angular frequency 10 rad/sec. A block of mass 2 kg is to be put on the disc frication coefficient between disc and block ismu_(K)= 0.4, then find the maximum distance from axis where the block can be placed without slidding: |
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Answer» Solution :`mu_(K)g = omega^(2)g` `0.4 xx 10 =(10)^(2) x` `x = 4/100 m = 4 cm` |
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