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A diver at a depth of 45 m exhales a bubble of air that is 1 cm in radius, Assumingideal gas behaviour, what will be the radius of this bubble as it breaks at the surface of the water? |
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Answer» Solution :`p_1 = rhogh +` ATM . PRESSURE , `P_2` = atm. Pressure APPLY `p_1V_1 = p_2V_2`, calculate `V_2` and then the radius 1.8cm |
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