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A domain in a ferromagnetic substance is in the form of a cube of volume 10^(-18)m^(3). Calculate the number of atoms present in the given volume and a hypothetical dipole moment and magnetisation of the domain ( given density of the substance 7.9xx 10^(3) "kgm"^(-3) molecular mass 55g / mole and dipole moment of each atom is 9.2 xx 10^(-24) "Am"^(2)). |
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Answer» Solution :Given VOLUME of the cube = `10^(-18) m^(3)` MASS = (volume ) (density ) `= 10^(-18) m^(3)xx7.9xx 10^(3) "kg m"^(-3)` i.g., `"" m = 7.9 xx 10^(-15) ` kg Number of atoms = `(7.9 xx 10^(-15) xx 6.0235 xx 10^(23))/(55xx10^(-3))` `= 0.865 xx 10 ^(11)` =` 8.65 xx 10 ^(10)` atoms |
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