A double convex thin lens made of glass ("refractive index" mu = 1.5) has both radii of curvature of magnititude 20 cm Incident light rays parallel to thte axis of the lens will converge at a distance L such that

A double convex thin lens made of glass ("refractive index" mu = 1.5)

1.	A double convex thin lens made of glass ("refractive index" mu = 1.5) has both radii of curvature of magnititude 20 cm Incident light rays parallel to thte axis of the lens will converge at a distance L such that
Answer» L = 20 cm L = 10 cm L = 40 cm L = 20/3 cm. Solution :(a) `(1)/(f)=(MU-1)((1)/(R_(1))-(1)/(R_(2)))` Give `R_(1) = + 20 cm, R_(2) = - 20 cm, mu = 1.5` `rArr = 20 cm`. Parallel rays converge at FOCUS. So L = f.

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A double convex thin lens made of glass ("refractive index" mu = 1.5) has both radii of curvature of magnititude 20 cm Incident light rays parallel to thte axis of the lens will converge at a distance L such that

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