A double slit apparatus is immersed in a liquid of refractive index 1.33. It has slit separation of 1mm and distance between the plane of slit and screen 1.33m. The slits are illuminated by a parallel beam of light whose wavelength in air is 6300A^(0). Calculate the fringe width.

A double slit apparatus is immersed in a liquid of refractive index 1.

1.	A double slit apparatus is immersed in a liquid of refractive index 1.33. It has slit separation of 1mm and distance between the plane of slit and screen 1.33m. The slits are illuminated by a parallel beam of light whose wavelength in air is 6300A^(0). Calculate the fringe width.
Answer» SOLUTION :As FRINGE width `BETA= (D lambda"/"d)` and by presence of medium the WAVELENGTH becomes `(lambda"/"mu)`, so the fringe width in liquid will be `beta.= (D lambda)/(mu d)= (1.33xx 6300xx 10^(-10))/(1.33xx 1 xx 10^(-3))= 0.63mm`.

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A double slit apparatus is immersed in a liquid of refractive index 1.33. It has slit separation of 1mm and distance between the plane of slit and screen 1.33m. The slits are illuminated by a parallel beam of light whose wavelength in air is 6300A^(0). Calculate the fringe width.

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