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A double slit apparatus is immersed in a liquid of refractive index 1.33. It has slit separation of 1mm and distance between the plane of slit and screen 1.33m. The slits are illuminated by a parallel beam of light whose wavelength in air is 6300A^(0). One of the slits of the apparatus is covered by a thin glass sheet of refractive index 1.53. Find the smallest thickness of the sheet to bring the adjacent minima on the axis. |
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Answer» <P> Solution :Now as the distance of a minima from adjacent maxima is `(BETA."/"2)`, so according to given problem, SHIFT`y_(0)= (D)/(d) (mu_(R ) -1)t= (beta.)/(2)""" with "mu_(r )= (mu_p)/(mu_M)` `(D)/(d)[(mu_p)/(mu_M)-1]t= (D lambda)/(2mu_(M)d)""i.e., t= (lambda)/(2(mu_(p)-mu_(M)))` So, `t= (6300xx 10^(-10))/(2(1.53-1.33))= 1.75 mu m`. |
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