A double slit experiment is immersed in a liquid of refractive index 1.33. Separation between the slits is 1.0 mm and the distance between slit and screen is 1.33 m. If slits are illumintated by a parallel beam of light whose wavelength is 6300 Å, then fringe width will be :

A double slit experiment is immersed in a liquid of refractive index 1

1.	A double slit experiment is immersed in a liquid of refractive index 1.33. Separation between the slits is 1.0 mm and the distance between slit and screen is 1.33 m. If slits are illumintated by a parallel beam of light whose wavelength is 6300 Å, then fringe width will be :
Answer» `6.3 mm` `63 mm` `0.63 mm` None of these. Solution :`lambda_(L) =(lambda_(AIR))/(mu_(l))` `BETA = (lambda D)/(d)` In LIQUID, `beta = (lambda_(l)D)/(d) = (lambda_(air).D)/(mu_(l).d) = 0.63 mm`

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A double slit experiment is immersed in a liquid of refractive index 1.33. Separation between the slits is 1.0 mm and the distance between slit and screen is 1.33 m. If slits are illumintated by a parallel beam of light whose wavelength is 6300 Å, then fringe width will be :

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