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A draws a card from a pack of `n`cards marked `1,2,ddot,ndot`The card is replaced in the pack and `B`draws a card. Then the probability that `A`draws a higher card than `B`is`(n+1)2n`b. `1//2`c. `(n-1)2n`d. none of theseA. `(n + 1)//2n`B. `1//2`C. `(n - 1)//2n`D. none of these |
Answer» Correct Answer - C If A draws card higher than B, then the number of favorable cases is (n - 1) + (n + 2) + … + 3 + 2 + 1 (as when B draws card number 1, then A can draw any card from 2 to n and so on). Therefore, the required probability is `(n((n-1))/(2))/(n^(2)) = (n-1)/(2n)` |
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