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A drop of water of 0.2 g mass is placed between two well cleaned glass plates, the distance between which is 0.01 cm. Find the force of attraction between the plates, |
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Answer» Solution :Suppose the drop spreads evenly and as SEEN from above has the shape of a circle of RADIUS R (Fig. 21.9). The AREA of this circle is `S = V//d = m//rhod`. The FORCE of Fig. 21.7. attraction between the plates is `F = DeltapsS` where `Deltap= 2 sigma//d` is the excess pressure under the curved surface. Therefore `F=2sigma m// rho d^(2)` |
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