1.

A dust particle of mass 10^(-6) gm moves between two walls separated by 1.0 mm. If speed of the particle is 10^(-4)ms^(-1) then nth state of the particle will be :

Answer»

`3 xx 10^(10)`
`3 xx 10^(15)`
`3 xx 10^(17)`
`3 xx 10^(27)`

Solution :`E_(N)=(n^(2)h^(2))/(8ML^(2))=1//2mv^(2)`
`n^(2)=(4M^(2) V^(2) l^(2))/(h^(2)) RARR n=(2mvl)/(h)`
`rArr n=3 xx 10^(17)`


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