(a) Explain the action of Cone. HCl on KMnO_4 crystals(b) Write the st – InterviewSolution

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1.	(a) Explain the action of Cone. HCl on KMnO_4 crystals(b) Write the structure of perchloric acid.
Answer» Solution :(a) When `KMnO_(4)`is treated with cone. HC1 chlorine is liberated. `2KMnO_(4) +16HCI —rarr 2KCl + 2MnCI_(2) + 8H_(2)O + 5Cl_(2)` (b)

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