1.

A face centered cubic solid of an element (atomic mass 60) has a cube edge of 4 Å. Calculate its density.

Answer»

Solution :For FCC UNIT cell n = 4
`"Edge length (a)"=4Å=4xx10^(-8)cm`
`"MASS (M)"="60 g MOL"^(-1)`
`"Density "(rho)=?`
`rho=(nM)/(a^(3)N_(A))`
`=(4xx"60 g mol"^(-1))/((4xx10^(-8)cm)^(3)xx(6.023xx10^(23)"mol"^(-1)))`
`=("240 g mol"^(-1))/(6.4xx10^(-23)cm^(3)xx6.023xx10^(23)"mol"^(-1))`
`=(240)/(38.54)GCM^(-3)`
`rho=6.227gcm6(-3)`


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