A family having 3 children in which at least one boy, then probability

1.	A family having 3 children in which at least one boy, then probability that family have one boy and one girl is –(A) 1/2(B) 1/3(C) 1/4(D) 3/4
Answer» Answer is (B) 1/3 Sample space of children in a family is : S = {B, G, G, B, B, G, B, B, G} Event of 2 boys and 1 girl A = {B, B, G} ∴ n(S) = 3, n(A) = 1 Thus, required probability = n(A)/n(S) = 1/3

A family having 3 children in which at least one boy, then probability that family have one boy and one girl is –(A) 1/2(B) 1/3(C) 1/4(D) 3/4

Answer»

Answer is (B) 1/3

Sample space of children in a family is :

S = {B, G, G, B, B, G, B, B, G}

Event of 2 boys and 1 girl A = {B, B, G}

∴ n(S) = 3, n(A) = 1

Thus, required probability = n(A)/n(S) = 1/3

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A family having 3 children in which at least one boy, then probability that family have one boy and one girl is –(A) 1/2(B) 1/3(C) 1/4(D) 3/4

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