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A farmer moves along a boundary of a square field 10m in 40sec. What will be the magnitude of displacementof the farmer at the end of 2 min 20 sec from his initial position ? |
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Answer» <P>Let the Initial position of farmer be P So, The DISTANCE COVERED by the farmer in 40 Sec = 4 × 10 = 40 m
Since, In 40 Sec farmer move 40m THUS , In 140sec ( 2min 20sec) Farmer will move 140m.
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