1.

.A father is 30 years elder than his son. After 8 years, he will be 4 times as old as his son. Find their present ages.​

Answer»

Father = 32 YEARS

SON = 2 years

Step-by-step explanation:

Given -

  • Father is 30 years elder than his son.
  • After 8 years, the father will be 4 times as old as his son.

To find -

  • Their present ages.

Solution -

Let the age of father be 'X' years.

Let the age of his son be 'y' years.

According to the first statement ,

x = y + 30--------1

Now , according to the second statement,

x + 8 = (y + 8)4

→ x + 8 = 4y + 32

→ y + 30 + 8 = 4y + 32 (from 1)

→ y + 38 = 4y + 32

→ 38 - 32 = 4y - y

→ 6 = 3y

→ 6/3 = y

→ 2 years = y (putting in 1)

x = 2 + 30

x = 32 years

Therefore, the present age of the father is 32 years and the present age of his son is 2 years.


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