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A faulty thermometer reads freezing point and boiling point of water as `-5 ^(@)C` abd `95^(@)C` respectively . What is the correct value of temperature as it reads `60^(@)C` on faulty thermometer?A. `60^(@)C`B. `65^(@)C`C. `64^(@)C`D. `62^(@)C` |
Answer» Correct Answer - B `(X-LFP)/(UPF-LFP)` = constant ( for all temperature scales ) where `LFP rarr` lower fixed point `UFP rarr` Upper fixed point `(X-(-5))/(95-(-5)) = (C-0)/(100-0) implies (60+5)/(95+5) = (C)/(100) implies C= 65^(@)C` |
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