1.

A fighter plane flying horizontally passes over an antiaircraft gun with a uniform velocity 200 ms^(-1) . The gun can fire the shell with a velocity 200sqrt(2)ms^(-1) . At what angle should the gun fire the shell so as to hit the plane ?

Answer»

`45^@`
`30^@`
`60^@`
`90^@`

Solution :Let velocity of SHELL = U and velocity of PLANE = V
and `theta` be the angle at which SHALL is fired to HIT the plane, then
`Ucostheta=Vimpliescostheta=V/U=200/(200sqrt(2))`
`costheta=1/sqrt(2)impliestheta=45^@`


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