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A first order decomposition reaction takes 40 minutes for 30% decomposition. Calculate its t_(1//2) value.

Answer»


Solution :`K=(2.303)/(t)log""(a)/(a-x)=(2.303)/(40" MIN")log""(a)/(a-0.30a)=0.0089" min"^(-1),t_(1//2)=(0.693)/(k)=(0.693)/(0.0089" min"^(-1))=77.86" min."`


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