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A first order reaction has a rate constant 1.15xx10^(-3)s^(-1). How long will 5 g of this reactant take to reduce to 3 g? |
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Answer» Solution :GIVEN : `[A]_(0)=5 g, [A]=3 g, k=1.15xx10^(-3)s^(-1)`. Applying first order KINETICS equation and substituting the values, we get `t=(2.303)/(t)"log"([A]_(0))/([A])=(2.303)/(1.15xx10^(-3)s^(-1))"log"(5g)/(3G)=2.00xx10^(3) (log 1.667)s` `=2.0xx10^(3) xx 0.2219s=443.8s` |
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