1.

A first order reaction has a rate constant of 0.0051" min"^(-1). If we begin with 0.10 M concentration of the reactant, what concentration of the reactant will remain in the solution after 3 hours ?

Answer»


Solution :`k=(2.303)/(t)log""([A]_(0))/([A]):.0.0051" MIN"^(-1)=(2.303)/(3xx60" min")log""(0.10)/([A])`
or `log""(0.10)/([A])=0.3986" or "(0.10)/([A])="ANTILOG "(0.3986)=2.5" or "[A]=(0.10)/(2.5)=0.04" M"`


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