1.

A first order reaction has a specific reaction rate of 10^(-2) sec^(-1) . How much time will it take for 20 g of the reactant to reduce to 5 g

Answer»

138.6 sec
346. 5 sec
693.0 sec
238 . 6 sec

Solution :HALF life of a FIRST order reaction
`t_(1//2) = (0.693)/(K) = (0.693)/(10^(-2)) = 69.3` sec
Method - 1

Total time = `2t_(1//2) = 2 xx 69.3= 138.6` sec
Method-2
`t = (2.303)/(K)` log `([A]_(0))/([A]_(t))`
`t = (2.303)/(10^(-2)) "log" (20)/(5) implies t = 138.6` sec


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