1.

A first order reaction has a specific rreaction rate of 10^(-2)s^(-1). How much time will it take for 20 g of the reactant of reduce to 5 g ?

Answer»

238.6 second
138.6 second
346.5 second
693.0 second

Solution :Given, ` k = 10^(-2) s^(-1).`
HENCE, `t_(1//2) = (0.693)/(k) = (0.693)/(10^(-2))` second
`20 g to 5 g ` takes TWO half LIVES
`( 20g to 10g to 5 g)`
Hence, `t =2 xx (0.693)/(10^(-2)) = 138*6` second


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