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A first order reaction is 15% complete in 20 min. how long it will take to complete 2 0 %

Answer»

for first order reactiont = 2.303 / K (Log a / a-x)Let a = 100initially reaction is 15% completed, so x = 15 , t = 20 mn.so, 20 = 2.303 / K ( log 100 / 100-15 ) K = 2.303 / 20 ( log 100 / 85 ) K = 2.303 / 20 (log 1.176 ) K = 2.303 / 20 ( 0.706 ) K = 0.11515 (0.706 ) K = 0.00813now reaction is 20% completedso, t = 2.303 / K (log a / a-x ) t = 2.303 / 0.00813 ( log 100 / 100-20 ) ( putting value of K ) t = 283.27 ( log 100 / 80) t = 27.45 min.

please solve step by step in last when putting value of K

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