1.

A first order reaction is 20% complete in 10 minutes. Calculate time taken for reaction to go to 80% .

Answer»

SOLUTION :`K=(2.303)/(t)log_(10).(100)/((100-20))`
`=(2.303)/(10)log_(10).(100)/(80)=0.223minute^(-1)`
Again applying first ORDER equation
`t=(2.303)/(K)log_(10).(100)/((100-80))`
`=(2.303)/(0.0233)log_(10).(100)/(20)=72.18min`.


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