1.

A first order reaction is 20% completed in 10 minutes. Calculate the time taken for the reaction to go to 80% completion.

Answer»

SOLUTION :Applying the FIRST order equation,
`k = (2.303)/(t) "log" ([R]_(0))/([R])`
At t= 10 min, R= 100-20
`:. K = (2303)/(t) "log"_(10) (100)/((100-20))`
`t= (2303)/(10) "log"_(10) (100)/(80)`
`=0.0223 "min"^(-1)`


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