1.

A first order reaction is 20% completed in 10 minutes . Calculate the time taken for the reaction to go to 80% completion.

Answer»

Solution :Applying the first ORDER equation,
`k=(2.303)/tlog.([R]_0)/([R])`
At t = 10 min , R100 -20
`:. k = (2303)/t log10100/((100-20))`
`:. k = (2303)/t LOG.(100)/(80)`
`= 0.0223"min"^(-1)`


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