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A first order reaction is 25% complete in 30 minutes. Calculate the specific reaction rate. |
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Answer» SOLUTION :`K=2.303/309"LOG"[A]_0/(75/100[A]_0)=2.303/30"log"4/3=(2.303xx0.1250)/30=0.0096 min^-1=9.6xx10^-3min^-1` `t_(1/2)=0.693/9.6xx10^3=6930/96=72.18min`.` |
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