1.

A first order reaction is 60% complete in 20 minutes .How long will the reaction take to be 84% complete ?

Answer»

54 mins
68 mins
40 mins
76 mins

SOLUTION :( C) For 60% COMPLETION of reaction
`k= (2.303)/(t) "log"([R]_(0))/([R])`
`=(2.303)/(20)"log" (100)/(40)`
`=0.045 "MIN^(-1)`
For 84 % completion of reaction
`t = (2.303)/(k)"log"([R]_(0))/([R])`
`=(2.303)/(0.045)"log"(100)/(16)`
=40.7 min


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