1.

A first order reaction is carried out with an initial concentrationof 10 molper litre an 80% of the reactant changes into the product in 10 sec. Now if the same reaction is carried out with an initial concentration of 5 mol per litre. The percentage of the reactant changing to the product in 10 sec is:

Answer»

40
80
60
50

Solution :`10M(80%)/(t=10"SEC")2M 5M(80%)/(t=10"sec")1M`


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