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A first order reaction is found to have a rate constant k=7.39xx10^(-5)sec^(-1). Find the half life of this reaction (log2=0.3010).

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SOLUTION :For a first order REACTION, `K=(2.303)/(t)LOG""(a)/(a-x)"":"""For "t=t_(1//2),x=a//2`
`t_(1//2)=(2.303)/(k)log""(a)/(a-a//2)=(2.303)/(k)log2=(2.303)/(7.39xx10^(-5)s^(-1))xx0.3010=9.38xx10^(3)s`


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