1.

A first order reaction takes 69.3 min for 50% completion. Set up on equation for determining the time needed for 80% completion.

Answer»

Solution :`K=0.693/t_(1//2)=0.693/69.3` min
`=10^(-2) "min"^(-1)`
`T=2.303/K "LOG"([R_0])/([R])`
`=2.303/10^(-2) log5`
=160.9 min


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