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A first order reaction takes 69.3 min for 50% completion. Set up on equation for determining the time needed for 80% completion. |
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Answer» Solution :`K=0.693/t_(1//2)=0.693/69.3` min `=10^(-2) "min"^(-1)` `T=2.303/K "LOG"([R_0])/([R])` `=2.303/10^(-2) log5` =160.9 min |
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