1.

A firstorderreactiontakes100 minforcompletionof 60 %of reaction ,Thetimeeequiredfor completionof 90% of thereactionis

Answer»

`150 MIN `
`200`min
`220.9`min
`246.6` min

Solution :Forthe orderreaction ,`k=(2.303)/(t)log""(C_(0))/(C_(t))`
Case I:
`C_(0)=100 M,C_(t) =100 -60 =40, t= 100 min`
`k=(2.303)/(100)xxlog""(100)/(40)`
`k=(2.303xx0.3979)/(100)`
case-II :
`C_(0)=100 M,C_(t)=100-90=10M `
`t=(2.303)/(k) log""(100)/(10)`
`=(2.303)/(k)` .... substitutingK from I
`=(2.303xx100)/(2.303xx0.3979)=245.6 min`


Discussion

No Comment Found

Related InterviewSolutions