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A fish looking up through the water sees the outside world, contained in a circular horizon. If the refractive index of water is 4/3 and the fish is 12 cm below the water surface, the radius of this circle (in cm) is ..... |
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Answer» `36root_2`  `SINC=(R)/(sqrt(R^2+D^2))` `1/n=(R)/(sqrt(R^2+D^2))` `(1)/(n^2)=(R^2)/(R^2+D^2)` `thereforeR^2+D^2=n^2R^2` `thereforeD^2=R^2(n^2-1)` `therefore(D^2)/(n^2-1)=R^2` `thereforeR=(D)/(sqrt(n^2-1))` `thereforeR=(12)/(sqrt((4/3)^2)-1)=(12)/(sqrt((16)/(9)-1))` `thereforeR=(36)/(sqrt7)` cm |
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