A fixed source of sound emitting a certain frequency appears as `f_(a)` when the observer is apporoaching the source with `upsilon_(0)` and `f_(r)` when the observer recedes from the source with the same speed. The frequency of source isA. (a) `(f_(r) + f_(a))/(2)`B. (b) `(f_(r) - f_(a))/(2)`C. (c ) `sqrt(f_(a) f_(r)`D. (d) `(2f_(r)f_(a))/(f_(a) + f_(a))`

A fixed source of sound emitting a certain frequency appears as `f_(a)

1.	A fixed source of sound emitting a certain frequency appears as `f_(a)` when the observer is apporoaching the source with `upsilon_(0)` and `f_(r)` when the observer recedes from the source with the same speed. The frequency of source isA. (a) `(f_(r) + f_(a))/(2)`B. (b) `(f_(r) - f_(a))/(2)`C. (c ) `sqrt(f_(a) f_(r)`D. (d) `(2f_(r)f_(a))/(f_(a) + f_(a))`
Answer» Correct Answer - A `f_(a) = f(nu + nu_(o)/(nu))` `:. nu_(o)/(nu )= f_(a)/(f) - 1` …(i) `f_(r) = f ((nu - nu_(o))/(nu))` `:. nu_(o)/(nu) = 1 - (f_(r))/(f)` …(ii) From Eqs. (i) and (ii), we get `f = (f_(a) + f_(r))/(2)`

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