A flask is initially filled with pure `N_2O_3(g)` having pressure 2 bar and following equilibria are established. `N_2O_3(g)hArrNO_2(g)+NO(g)" "K_(P_1)=2.5bar` `2NO_2(g)hArrN_2O_4(g)" "K_(P_2)=?` If at equilibrium partial pressure of NO(g) was found to be 1.5 bar,then:A. Equilibrium parial pressure of `N_2O_3(g)` is 0.5 bar.B. Equilibrium partial pressure of `NO_2(g)` is 0.83 bar.C. Equilibrium parital pressure of `N_2O_4` is 0.33 bar.D. Value of `K_(P_2)` is 0.48 bar

A flask is initially filled with pure `N_2O_3(g)` having pressure 2 ba

1.	A flask is initially filled with pure `N_2O_3(g)` having pressure 2 bar and following equilibria are established. `N_2O_3(g)hArrNO_2(g)+NO(g)" "K_(P_1)=2.5bar` `2NO_2(g)hArrN_2O_4(g)" "K_(P_2)=?` If at equilibrium partial pressure of NO(g) was found to be 1.5 bar,then:A. Equilibrium parial pressure of `N_2O_3(g)` is 0.5 bar.B. Equilibrium partial pressure of `NO_2(g)` is 0.83 bar.C. Equilibrium parital pressure of `N_2O_4` is 0.33 bar.D. Value of `K_(P_2)` is 0.48 bar
Answer» Correct Answer - A::B::C::D

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