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A flat curve an a highway has a radius of curvature 400 m. A car goes around a curve at a speed of 32 m//s. What is the minimum value of coefficient of friction that will prevent the car from sliding ? (g=9.8 m//s^(2)) |
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Answer» Solution :Given: `r = 400m, v=32 m//s` Maximum safety speed of car along curved horizontal road to prevent SLIDING is `v=sqrt(mu RG)` `32^(2)=mu XX 400 xx 9.8` [SQUARING on both SIDES] `mu=((32)^(2))/(400xx9.8)` `mu=0.261` |
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