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A flat search coil of 100 turns and each of area 3xx10^(-4)m^(2) is connected to a galvanometer, so that the total resistance of the circuit is 90Omega. The plane of the coil is normal to a magnetic field, B = 0.4T. Calculate the change in flux when the coil is moved to a region of negligible magnetic field and the charge passes through the galvanometer. |
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Answer» Solution :`A=3xx10^(-4)m^(2),N=100,R=90Omega,B=0.4T` Magnetic FLUX `(phi_(B))=NAB=100xx3xx10^(-4)xx0.4=1.2xx10^(-2)` weber `phi_(B)=1.2xx10^(-2),phi_(B)=0` `THEREFORE` Charge `Q=(phi_(B)-phi_(B).)/(R)=(1.2xx10^(-2))/(90)=1.33xx10^(-4)C` |
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